[英]Instagram scraping: How to get the Instagram Profile Name using selenium Python
Good afternoon, I'm currently attempting to retrieve the following field of a certain instagram profile (the profile's name [ not the username ] as shown below the username.下午好,我目前正在尝试检索某个 instagram 个人资料的以下字段(个人资料的名称 [不是用户名],如下所示的用户名。
Therefore, I'm looking for the code to get the field: "yereni028k" (the profile's name, that is).因此,我正在寻找获取该字段的代码:“yereni028k”(即配置文件的名称)。 I do have the following code to retrieve the other data in the profile:
我确实有以下代码来检索配置文件中的其他数据:
posts = wait.until(EC.presence_of_element_located((By.XPATH, '//li/span[text()=" posts"]/span'))).text
followers = wait.until(EC.presence_of_element_located((By.XPATH, '//li/a[text()=" followers"]/span'))).text
following = wait.until(EC.presence_of_element_located((By.XPATH, '//li/a[text()=" following"]/span'))).text
name = ( ..... ) #profile's name
Thanks for all your help.感谢你的帮助。
If you can have a try with below code:如果您可以尝试以下代码:
name = wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, ".-vDIg h1"))).text
user_name = wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "_7UhW9.fKFbl.yUEEX.KV-D4.fDxYl"))).text
Css selectors are a better way to get element. Css 选择器是获取元素的更好方法。
"UPDATE" if you wanna use Xpath then use the below code: “更新”如果你想使用 Xpath 然后使用下面的代码:
name = wait.until(EC.presence_of_element_located((By.XPATH, "/html/body/div[1]/section/main/div/header/section/div[2]/h1"))).text
user_name = wait.until(EC.presence_of_element_located((By.XPATH, "/html/body/div[1]/section/main/div/header/section/div[1]/h2"))).text
use the code as below使用如下代码
driver.find_element_by_xpath("//a[contains(.,'followers')]/ancestor::ul/following-sibling::div/h1).text
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