[英]How to get the largest number for each item in the table MySql
How to get the largest number for each item in the table MySql如何获取表MySql中每个项目的最大数
I want to have the most chosen name "name_p" everywhere "num_place"我想在“num_place”处都有选择最多的名字“name_p”
SELECT name_p,num_place,COUNT(`id`) as couny_pla FROM selec_user GROUP BY name_p,num_place ORDER BY selec_user.num_place ASC
this result:-这个结果:-
But this is the result I needed但这是我需要的结果
This can produce your desired result but may arbitrarily either 'e' or 'h' for num_place 3, since they are tied:这可以产生您想要的结果,但对于 num_place 3 可能是任意的“e”或“h”,因为它们是绑定的:
select name_p, num_place, couny_pla
from (
select name_p, num_place, row_number() over (partition by num_place order by couny_pla desc) n, count(*) couny_pla
from selec_user
group by name_p, num_place
) ranked_groups
where n=1
order by num_place;
Replace row_number()
with rank()
if you want all tied values returned.如果要返回所有绑定值,请将
row_number()
替换为rank()
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.