创建一个 Python 字典，其中每个键都有一个列表作为值

Question

I am trying to create a dictionary below with the results to like;

{'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7'}

list1 = ('1','2','3','4','5','6','7')
counter = 0
for x in list1:
    counter =  counter+1
    d = {
        x:counter
    }

but the results I am getting are: {'7': 7}

Answer 1

Use a dict comprehension:

d = {x: int(x) for x in list1}

or

d = {x: i+1 for i, x in enumerate(list1)}

If you want to still have the loop, try:

list1 = ('1','2','3','4','5','6','7')
counter = 0
for x in list1:
    counter =  counter+1
    d[x] = counter

or d.update({x: counter}) instead of d[x] = counter .

Answer 2

You are reassigning d on every iteration.

Either way, you can do this with a dictionary comprehension and enumerate :

>>> list1 = ('1','2','3','4','5','6','7')
>>> d = {x: counter for counter, x in enumerate(list1, 1)}
{'1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7}

Answer 3

dict1 = { x: int(x) for x in list1 }

Answer 4

You create a new dict each time

Start one and add to it

d = {}
for foo in bar:
    d[foo] = baz

Answer 5

That is because you erase the variable d at each iteration.

You want to add the new key and value to an already existing dictionary (created empty: d = {} ), with d[x] = counter .