将文本文件转换为以行号为值的字典

Question

I have to convert text file into dictionary and use line number as a value for dictionary.

Example text file 'test.txt':

aaaa 4.5

bbbb

3 cccc dddd

Output I need to get is dictionary looking like this:

{'aaa':1, 4.5:1, 'bbbb':2, 3:3, 'cccc':3, 'dddd':3}

Answer 1

I think this should work as in the above answer the last string will contain \n

val = 1
dic = {}
with open("a.txt") as a:
    for line in a:
        a = line.split(" ")
        for ech in a:
            dic[ech.replace("\n","")] = val
        val += 1

print(dic)

Answer 2

This is a simple way to do it:

filename = "C:/Users/henri/Downloads/test.txt"    # your own filename
f = open(filename, 'r')                           # open file reader
lis = f.readlines()                               # read all lines into a list
dic = {}                                          # make empty dictionary

for i,line in enumerate(lis):                     # loop through lines
    line = line.rstrip("\n")                      # remove trailing newline
    parts = line.split()                          # split into all parts of line

    for a in parts:                               # loop thourhg all the parts of the line
        dic[line] = i+1                           # add to dictionary

print(dic)

edit: didnt see that you wanted to split the lines at whitespaces, added it...

Answer 3

dct = {} with open('file.txt') as f: for index, line in enumerate(f): for token in line.split(): dct[token] = index+1 print(dct)