从 SpringBootApplication 中的 ClientResponse 获取正文

Question

I'm new to spring boot application. I want to get the response from there in string. this is my code.

String accessURL = serverURL + "itim/rest/accesscategories";
        RestClient rc4 = new RestClient(ResourceBuilder.getClientConfig());
        Resource r4 = rc4.resource(accessURL);
        r4.cookie(ltpaToken);
        r4.cookie(jsessionid);
        r4.cookie(csrftoken);
        r4.header("Content-Type", "application/json");
        ClientResponse resp4 = r4.get();

right now i'm doing this:

System.out.println(resp4.getStatusCode());
        System.out.println(resp4.getStatusType());
        System.out.println(resp4.getHeaders());

and i get this responce:

200
OK
CaseInsensitiveMultivaluedMap [map=[Cache-Control=no-cache,no-store,max-age=0,Content- 
Language=en-US,Content-Type=application/vnd.ibm.isim-v1+json,Date=Sat, 24 Apr 2021 02:22:32 
GMT,Expires=Thu, 01 Jan 1970 00:00:00 GMT,Pragma=No-cache,Set- 
Cookie=com.ibm.isim.lastActivity=Bj7WAcMo3apevFKD4JoHyr4iKepdA8AVptb3S7eRM5c%3D; Path=/itim; 
Secure; HttpOnly,Set-Cookie=com.ibm.isim.maxInactive=1800; Path=/itim; Secure,Strict- 
Transport-Security=max-age=31536000; includeSubdomains,Strict-Transport-Security=max- 
age=31536000; includeSubdomains,Transfer-Encoding=chunked,X-FRAME-OPTIONS=SAMEORIGIN]]

Answer 1

Use response.getBody() function or simply response.body if you're using any frontend framework.

Answer 2

You probably want to do something like this, so you can process the JSON response (unless you already have JSON serialization/de-serialization for a POJO set up elsewhere).

JsonNode body = resp4.bodyToMono( JsonNode.class ).block();

You could do something simple like this to test.

System.out.println( resp4.bodyToMono( String.class ).block() );

Take a look at the documentation for ClientResponse and Mono<T> for more details.