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如何在 python 中的递归 function 中维护全局变量?

[英]How to maintain a global variable in recursive function in python?

Unable to keep a track of the variable maxSum, after recursive calls it keeps resetting back to 0, despite passing it as a parameter in calls.无法跟踪变量 maxSum,在递归调用之后,尽管在调用中将其作为参数传递,它仍会一直重置回 0。 The function maxPathSum should return 11 but it's returning 0. function maxPathSum 应该返回 11,但它返回 0。

class TreeNode:
    def __init__(self, val, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right

def maxPathSum(node):
    sums = []
    maxPath = []
    maxSum = 0
    recursiveSum(node, 0, maxSum, sums)
    return maxSum


def recursiveSum(node, ssum, maxSum, sums):
    if node == None:
        return
    
    if maxSum < ssum + node.val and node.left == None and node.right == None:
        maxSum = ssum + node.val
            
    sums.append(maxSum)
    
    # traverse left subtree
    recursiveSum(node.left, ssum + node.val, maxSum, sums)
    # traverse right subtree
    recursiveSum(node.right, ssum + node.val, maxSum, sums)


root = TreeNode(1)
root.left = TreeNode(2)
root.right = TreeNode(3)
root.left.left = TreeNode(4)
root.left.right = TreeNode(5)
root.right.left = TreeNode(7)
root.right.right = TreeNode(6)
print(maxPathSum(root))

You can achieve your goal by one of the following two modifications.您可以通过以下两种修改之一来实现您的目标。

Since you build a list from the maxSum values, you can simply change the last line of your maxPathSum function so:由于您从maxSum值构建列表,因此您可以简单地更改maxPathSum function 的最后一行:

def maxPathSum(node):
    sums = []
    maxPath = []
    maxSum = 0
    recursiveSum(node, 0, maxSum, sums)
    return max(sums)

Or you can use the maxSum variable, but for this you must do some small modifications in both functions:或者您可以使用maxSum变量,但为此您必须在两个函数中进行一些小的修改:

def maxPathSum(node):
    sums = []
    maxPath = []
    maxSum = 0
    maxSum=recursiveSum(node, 0, maxSum, sums)
    return maxSum

def recursiveSum(node, ssum, maxSum, sums):
    if node == None:
        return
    
    if maxSum < ssum + node.val and node.left == None and node.right == None:
        maxSum = ssum + node.val
            
    sums.append(maxSum)
    
    # traverse left subtree
    s=recursiveSum(node.left, ssum + node.val, maxSum, sums)
    if s!=None: maxSum=max(maxSum,s)
    # traverse right subtree
    s=recursiveSum(node.right, ssum + node.val, maxSum, sums)
    if s!=None: maxSum=max(maxSum,s)
    return maxSum

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