如何通过设置结束条件打印从素数分解 output 显示的中间星号？

Question

The following code inputs an integer (n) from the user and outputs the prime decomposition of n. I'm trying to set an "end" condition for the output of this part of the code but I can't:

 if(countA == 1)
        cout<<2;
    else if(countA != 0)
        cout<<2<<"^"<<countA;

An example for the correct output is:

Input: 100

Output: 2^2*5^2

But what it's printing now is without the middle asterisk (between 2 and 5):

2^25^2

The entire code:

#include <iostream>
#include <cmath>

using namespace std;
int main()
{
    int n, countA = 0, countB = 0;
    cin>>n;
    while(n % 2 == 0)
    {
        n /= 2;
        countA++;
    }
    if(countA == 1)
        cout<<2;
    else if(countA != 0)
        cout<<2<<"^"<<countA;
    for(int i = 3, end = sqrt(n); i <= end; i = i + 2)
    {
        while(n % i == 0)
        {
            n /= i;
            countB++;
        }
        if(countB == 1)
            cout<<i<<"*";
        else if(countB != 0)
        {
            cout<<i<<"^"<< countB;
            if(!(i + 1 >= end))
                cout<<"*";
        }
    }
    if(n > 2)
        cout<<n;
    return 0;
}

Answer 1

#include <iostream>
#include <cmath>
using namespace std;

const char *pad = "";
int main()
{
    int n, countA = 0, countB = 0;
    cin>>n;
    while(n % 2 == 0)
    {
        n /= 2;
        countA++;
    }
    if(countA > 0)
    {
        cout<<pad;   
        cout<<2;     
        if(countA > 1)
        {
            cout<<"^"<<countA;
        }
        pad = "*";
    }
    for(int i = 3; i <= sqrt(n); i = i + 2)
    {
        countB = 0;
        while(n % i == 0)
        {
            n /= i;
            countB++;
        }
        if(countB > 0)
        {
            cout<<pad;
            cout<<i;
            if(countB > 1)
            {
                cout<<"^"<<countB;
            }
            pad = "*";
        }
    }
    if(n > 2)
    {
        cout<<pad;
        cout<<n;
        pad = "*";
    }
    return 0;
}