引发 TimeoutException（消息，屏幕，堆栈跟踪）selenium.common.exceptions.TimeoutException：消息

Question

i get this error when i'm trying to access the login page in flickr "raise TimeoutException(message, screen, stacktrace) selenium.common.exceptions.TimeoutException: Message"

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome(executable_path="C:\\chromedriver.exe")

driver.get("https://www.flickr.com/")
driver.maximize_window()
wait = WebDriverWait (driver, 10)
element = wait.until(EC.element_to_be_clickable((By.XPATH, "//a[@id='yui_3_16_0_1_1619317268956_93511']")))
element.click()

Answer 1

No element located by //a[@id='yui_3_16_0_1_1619317268956_93511'] xpath is presented on https://www.flickr.com/ home page.
You should use //a[contains(@href,'signin')] instead

Answer 2

If your target is the login button, please use the bellow css selector:

element = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a[href*='signin']")))

But if you still want use xpath, the suggest @Prophet is right.

But note css selector more faster than xpath.