[英]How to deserialize child nodes of xml file
I've created an app using Xamarin Android.我使用 Xamarin Android 创建了一个应用程序。 Plan is for it to open a read-only copy of Clients.xml from the Assets folder and create a copy in internal storage for future editing.
计划是从 Assets 文件夹中打开 Clients.xml 的只读副本,并在内部存储中创建副本以供将来编辑。 The default file has a root node of clients and half a dozen child nodes of client.
默认文件有一个客户端根节点和六个客户端子节点。
I've got it to the point where it reads the asset and creates a local file but only with the first child node in it.我已经达到了读取资产并创建本地文件的程度,但仅包含第一个子节点。 I can't quite get it to an array of child nodes.
我不能把它放到一个子节点数组中。
What do I need to do to read all the child nodes?我需要做什么才能读取所有子节点?
Reading of the asset and creating a local file.读取资产并创建本地文件。
// Get storage path
path = System.Environment.GetFolderPath(System.Environment.SpecialFolder.Personal);
// Create clients file on first build
string filename = System.IO.Path.Combine(path, "Clients.xml");
if (!File.Exists(filename))
{
clients clients;
// Load read-only asset from file
var xmlSerialSettings = new XmlSerializer(typeof(clients));
using (StreamReader sr = new StreamReader(Android.App.Application.Context.Assets.Open("Clients.xml"), true))
{
clients = (clients)xmlSerialSettings.Deserialize(sr);
}
// Save local version to edit
var xsw = new XmlSerializer(typeof(clients));
using (StreamWriter sw = new StreamWriter(filename, false))
{
xsw.Serialize(sw, clients);
}
}
Clients.xml客户.xml
<?xml version="1.0" encoding="utf-8" ?>
<clients>
<client id="1">
<name>Bob</name>
<address>Home</address>
<postcode>CO1</postcode>
<email>bob@home.com</email>
<landline></landline>
<mobile>07784</mobile>
</client>
<client id="2">
<name>...</name>
<address>...</address>
<postcode>...</postcode>
<email>...</email>
<landline>...</landline>
<mobile>...</mobile>
</client>
....
</clients>
Clients.cs客户端.cs
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Serialization;
namespace QuoteBuilder
{
[Serializable, XmlRoot("clients")]
public class clients
{
[XmlElement("client")]
public client client { get; set; }
public clients()
{
}
public clients(client client)
{
this.client = client;
}
}
public class client
{
public string name { get; set; }
public string address { get; set; }
public string postcode { get; set; }
public string email { get; set; }
public string landline { get; set; }
public string mobile { get; set; }
public client()
{
}
public client(string name, string address, string postcode, string email, string landline, string mobile)
{
this.name = name;
this.address = address;
this.postcode = postcode;
this.email = email;
this.landline = landline;
this.mobile = mobile;
}
}
}
Inside your clients class you defined a member - client.在您的客户 class 中,您定义了一个成员 - 客户。 It is not a collection, and when you deserialize xml file to clients class it deserialize only one node (first).
它不是一个集合,当您将 xml 文件反序列化到客户端 class 时,它只反序列化一个节点(第一个)。 Use List or other collections inside:
使用 List 或其他 collections 里面:
[Serializable, XmlRoot("clients")]
public class Clients
{
[XmlElement("client")]
public List<Client> client { get; set; } // Collection
public Clients()
{
}
public Clients(List<Client> client)
{
this.client = client;
}
}
Also use CamelCase naming for classes, and lowerCase naming for variables - it is more readable还对类使用 CamelCase 命名,对变量使用小写命名 - 它更具可读性
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