在 append 中查找项目的索引值

Question

dupes is a list of duplicate items found in a list. clipb is the original list.

I now search for a part string of dupes in clipb . The aim at the end of the day is to append the word "duplicate" to the original list per duplicate item found.

dupes = ['0138', '0243']
clipb = ['ABC2b_0243D_K6_LOPA-PAST', 'ABC2b_0016G_M1_LOPA-PABR', 'ABC2b_0138H_M1_LOBR-BRMU', 'ABC2b_0138G_J1_LOPA-PAST', 'ABC2b_0243A_O§_STMA-MACV']

def Filter(clipb, dupes):
    return [str for str in clipb if
            any(sub in str for sub in dupes)]
            #index = clipb.index(clipb)  <<--- no idea how to add it in here 
    
rs_found = (Filter(clipb, dupes))
print ("found dupicates from the original list are: ","\n", rs_found)

Current output is only the list of duplicates found. Found duplicates from the original list are:

['ABC2b_0243D_K6_LOPA-PAST', 'ABC2b_0138H_M1_LOBR-BRMU', 'ABC2b_0138G_J1_LOPA-PAST', 'ABC2b_0243A_O§_STMA-MACV']

My problem is that I have no idea how to format the Filter to include outputting the index of found duplicates so I can actually change the items.

Answer 1

Instead of just filtering out the duplicates, since you want the duplicate items with a tab and 'DUPLICATE' appended to it, just do that when you find a duplicate, instead of filtering it out:

clipb = ['ABC2b_0243D_K6_LOPA-PAST', 'ABC2b_0016G_M1_LOPA-PABR', 'ABC2b_0138H_M1_LOBR-BRMU',
         'ABC2b_0138G_J1_LOPA-PAST', 'ABC2b_0243A_O§_STMA-MACV']

seen = set()
final = []
for item in clipb:
    tag = item[6:10]  # assuming tags are always at this index
    if tag in seen:
        item += '\tDUPLICATE'  # or '<space>DUPLCATE', as needed
    else:
        seen.add(tag)
    final.append(item)

print(final)
# Output:
['ABC2b_0243D_K6_LOPA-PAST',
 'ABC2b_0016G_M1_LOPA-PABR',
 'ABC2b_0138H_M1_LOBR-BRMU',
 'ABC2b_0138G_J1_LOPA-PAST\tDUPLICATE',
 'ABC2b_0243A_O§_STMA-MACV\tDUPLICATE']

Note that you don't need to pre-create a list of the duplicate tags - thats' done in the code; vaguely adapted from unique_everseen recipe from https://docs.python.org/3/library/itertools.html .

Answer 2

Your current direction is quite good. You don't really need the index here at all! You are using any(sub in str for sub in dupes) to check if any of the duplicated patterns is in the string which is good. You only a small logical refinement.

What should happen when the condition above is true? You want to add the "duplicate" string. What happens if it is not true? Add the original string as is. So just modify the list comprehension to be:

def Filter(clipb, dupes):
    return [s + " duplicate" if any(sub in s for sub in dupes) 
            else s
            for s in clipb]

^{* Note that I changed the str variable's name because str is the built-in type's name.}

The output with your sample data is:

found dupicates from the original list are:  
 ['ABC2b_0243D_K6_LOPA-PAST duplicate', 'ABC2b_0016G_M1_LOPA-PABR', 'ABC2b_0138H_M1_LOBR-BRMU duplicate', 'ABC2b_0138G_J1_LOPA-PAST duplicate', 'ABC2b_0243A_O§_STMA-MACV duplicate']

---

If you want to change the original list in-place, you can use the built-in enumerate() function to iterate over index and item:

for i, s in enumerate(clipb):
    if any(sub in s for sub in dupes):
        clipb[i] = s + " duplicate"