[英]What is the best practice to give a namespace for a bunch of static methods?
I need a namespace within a module for many different static methods doing similar jobs.我需要一个模块中的命名空间,用于执行类似工作的许多不同 static 方法。 From my research I learnt that having a class full of static methods is considered anti-pattern in Python programming:
从我的研究中我了解到,在 Python 编程中,拥有一个充满 static 方法的 class 被认为是反模式:
class StatisticsBundle:
@staticmethod
def do_statistics1(params):
pass
@staticmethod
def do_statistics2(params):
pass
If this isn't a good solution, what is the best practice instead that allows me to do a namespace lookup like getattr(SomeNameSpace, func_name)
within the same module?如果这不是一个好的解决方案,那么最好的做法是什么?它允许我在同一个模块中进行类似
getattr(SomeNameSpace, func_name)
的命名空间查找?
Use a package.使用 package。 Place the functions in a separate module, without using a class.
将函数放在单独的模块中,而不使用 class。
Within the statistics folder on your computer define 2 modules:在您计算机上的统计文件夹中定义 2 个模块:
helpers.py
where you define the helper functions. helpers.py
用于定义辅助函数。__init__.py
where you write the bulk of your code. __init__.py
用于编写大部分代码的地方。 You may rename the helpers
module, if you can come up with a better name for the group of functions you define within it.如果您可以为您在其中定义的一组函数想出一个更好的名称,您可以重命名
helpers
模块。 However, the __init__
module of a package is special.但是,package 的
__init__
模块是特殊的。 When the package is imported, the __init__
module is given the package name and evaluated.当 package 被导入时,
__init__
模块被赋予 package 名称并被评估。
To apply your example:要应用您的示例:
#statistics\helpers.py
def do_statistics1(params):
pass
def do_statistics2(params):
pass
# Rest of module omitted
#statistics\__init__.py
# Relative import
from . import helpers
# Get function using getattr()
do_statistics1 = getattr(helpers, "do_statistics1")
# Get function using dot notation
do_statistics2 = helpers.do_statistics2
# Rest of module omitted
Be sure to test the package by importing it.请务必通过导入来测试 package。 Relative imports do not work when evaluating a module within a package.
评估 package 中的模块时,相对导入不起作用。
In conclusion, you can get attributes from a module just like you can from a class.总之,您可以像从 class 中一样从模块中获取属性。
[...] what is the best practice instead that allows me to do a namespace lookup like
getattr(SomeNameSpace, func_name)
within the same module?[...] 最佳
getattr(SomeNameSpace, func_name)
是什么?
Python functions are first-class functions . Python 函数是一流的函数。 Hence, the simplest namespace is a
dict
(which actually isn't far from how instance namespaces work on __dict__
).因此,最简单的命名空间是
dict
(实际上与实例命名空间在__dict__
上的工作方式相距不远)。 If you want to implement a sort of factory function, it's just:如果你想实现一种工厂 function,它只是:
def _create_foo():
return Foo(...)
def _create_bar():
return Bar(...)
_my_ns = {
'foo': _create_foo,
'bar': _create_bar,
}
def my_factory(name):
return _my_ns[name]()
Also in runtime (given how staticmethod
descriptor works in Python 3) they will be of the same types.FunctionType
.同样在运行时(考虑到
staticmethod
方法描述符在 Python 3 中的工作方式)它们将具有相同的types.FunctionType
。
>>> class ns:
...
... @staticmethod
... def foo():
... pass
...
... type(ns.foo)
<class 'function'>
>>> type(_my_ns['foo'])
<class 'function'>
Depending on your python version, you might be able to use a SimpleNamespace根据您的 python 版本,您可能可以使用SimpleNamespace
import types
def foo():
print("foo")
def bar():
print("bar")
namespace = types.SimpleNamespace(foo=foo, bar=bar)
namespace.foo()
namespace.bar()
I need a namespace within a module for many different static methods doing similar jobs.我需要一个模块中的命名空间,用于执行类似工作的许多不同 static 方法。 From my research I learnt that having a class full of static methods is considered anti-pattern in Python programming:
从我的研究中我了解到,在 Python 编程中,拥有一个充满 static 方法的 class 被认为是反模式:
class StatisticsBundle:
@staticmethod
def do_statistics1(params):
pass
@staticmethod
def do_statistics2(params):
pass
If this isn't a good solution, what is the best practice instead that allows me to do a namespace lookup like getattr(SomeNameSpace, func_name)
within the same module?如果这不是一个好的解决方案,那么最好的做法是什么?它允许我在同一个模块中进行类似
getattr(SomeNameSpace, func_name)
的命名空间查找?
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