井中蜗牛 javascript 挑战

Question

This is my first question on stack overflow although this question had been answered before I didn't get enough details to understand why the code was written that way and I didn't just want to copy and paste the solution without understanding it.

The snail climbs 7 feet each day and slips back 2 feet each night, How many days will it take the snail to get out of a well with the given depth? Sample Input 31 Sample Output 6 this is was what i wrote but it didn't work

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
let climb = 0, days = 0;
   for(climb + 7; climb < depth; days++){
       climb += 2;
       console.log(days);
   

Answer 1

Just take input and write this var day= Math.ceil((depth-2)/5); and output that!

Answer 2

/* day --> 7++
night --> 2-- */
var day = 0;
var total = 0;
var input = 41;
 while (input>total){
     day++;
     total+=7;
   if (total>=input){
       console.log(day);
       break;
   }
   total = total -2
 }

Answer 3

As mentioned in the comments, no need to loop. Just work out the math of the problem an use that.

 function snailCalc (depth, dailyGain, nightlyLoss) { var days = 1; var netGain = dailyGain-nightlyLoss; if(depth > dailyGain ) { //Basic calc based on net gain taking the first day into account days = (depth-dailyGain)/netGain; //Add the fist day days += 1; //We want whole days so use Mathc.ceil days = Math.ceil(days) //Or we could do all that in one line //days = Math.ceil(((depth-dailyGain)/netGain) + 1); } return days; } const gain = 7; const loss = 2 for(var d = 1; d < 31; d++) { console.log(`Depth: ${d}, Days: ${snailCalc(d, gain, loss)}` ) }

 Bob

Answer 4

function main() {
    var depth = parseInt(readLine(), 10);
    console.log(Math.round(depth / 5))
}

Answer 5

try this:

  var depth = parseInt(readline(), 10);
  var day = 0;
  for(let climb = 0; climb <= depth;) {
      day +=1;
      climb += 7;
      if(climb >= depth) {
          break;
      }
      climb -= 2;
  }
  console.log(day);

Answer 6

 function main() {
 var depth = parseInt(readLine(), 10);
//your code goes here
var days=1;
var level =0;
for(level =0;level<depth;days++){
    level+=7
    if(level<depth){
        level-=2;
    } else{
        break ;
    }
    
}console.log(days)

}

Answer 7

Try this, I had the same trouble a couple days ago and we find the error is that using js you need to reset the variable where you sum the result before evaluate again if the distance the snail climbed that day is greater than the depth to end the clycle.

depth = 31;
let days = 0;
let climb = 0;

while(climb < depth){
    let result = climb + 7;
    if(result  >= depth){ 
        days++;
        break;
    }
    climb = result - 2;
    days++;
    //console.log("climb ",climb);

}

console.log(days);

Answer 8

You can change the function input and test the snipet:

for more you can run code and check result ↗

Eg: main(128) // 26

 function main(input) { let depth = input let climbsUp = 7 let slipsBack = 2 let distance = climbsUp - slipsBack let days = 0; let rDepth = Math.round(depth / distance) for (let i = 0; i < rDepth; i++) { distance = distance + 5 days = ++days if (days === 6) { console.log('days will it take the snail to get out of a well: ' + rDepth) } else { console.log('days will it take the snail to get out of a well: ' + rDepth) break; } } } main(42); main(128);