[英]Split Dataframe to multiple Dataframes by sub columns
I could not find an elegant way to split this table:我找不到一种优雅的方式来拆分这张桌子:
Open Close High
stock1 stock2 stock1 stock2 stock1 stock2
.. .. .. .. .. ..
Where stocks are sub columns, into multiple tables each for a stock, so first table is股票是子列,分成多个表,每个表对应一个股票,所以第一个表是
df_stock1 df_stock1
Open Close High
so a table/dataframe for each stock ( could be > 2 ) then return an array of those dataframes
.所以每个股票的表/数据框(可能> 2)然后返回这些
dataframes
的数组。
You could do something like this.你可以做这样的事情。 Here's a fictiv dataframe:
这是一个虚构的 dataframe:
import pandas as pd
import numpy as np
np.random.seed(123)
df = pd.DataFrame(np.random.randint(1, 10, (6, 6)),
columns=pd.MultiIndex.from_product([['Open', 'Close', 'High'],
['Stock1', 'Stock2']]))
which prints:打印:
Open Close High
Stock1 Stock2 Stock1 Stock2 Stock1 Stock2
0 3 3 7 2 4 7
1 2 1 2 1 1 4
2 5 1 1 5 2 8
3 4 3 5 8 3 5
4 9 1 8 4 5 7
5 2 6 7 3 2 9
Then to split your multi-index df, do the following, using groupby and DataFrame.xs:然后拆分您的多索引 df,使用 groupby 和 DataFrame.xs 执行以下操作:
Split = {idx: df_sub.xs(idx, level=1, axis=1) for idx,df_sub in df.groupby(level=1, axis=1)}
print(Split['Stock1'])
where df_sub
refers to the first-level of the multiindex df.其中
df_sub
指的是多索引 df 的第一级。 This givess:这给出了:
Open Close High
0 3 7 4
1 2 2 1
2 5 1 2
3 4 5 3
4 9 8 5
5 2 7 2
and和
Split2 = {idx: df_sub.xs(idx, level=1, axis=1) for idx,df_sub in df.groupby(level=1, axis=1)}
print(Split2['Stock2'])
prints:印刷:
Open Close High
0 3 2 7
1 1 1 4
2 1 5 8
3 3 8 5
4 1 4 7
5 6 3 9
EDIT Other levels
编辑其他级别
Similarily, if you want all the Open stocks, you can do this:同样,如果你想要所有的 Open 股票,你可以这样做:
Split_open = {idx: df_sub.xs(idx, level=0, axis=1) for idx,df_sub in df.groupby(level=0, axis=1)}
print(Split_open['Open'])
which returns:返回:
Stock1 Stock2
0 3 3
1 2 1
2 5 1
3 4 3
4 9 1
5 2 6
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