[英]Extract part of the string elements in an array using jq
I'm trying to extract part of the string in elements of an array, and create a new array with these extractions.我正在尝试提取数组元素中的部分字符串,并使用这些提取创建一个新数组。
[
"local/binaries/app-2.21.0.tar.gz",
"local/binaries/app-2.20.0.tar.gz",
"local/binaries/app-2.19.1.tar.gz",
"local/binaries/app-2.19.0.tar.gz",
"local/binaries/app-2.18.0.tar.gz"
]
Desired output所需 output
[
"app-2.21.0",
"app-2.20.0",
"app-2.19.1",
"app-2.19.0",
"app-2.18.0"
]
You can use jq's capture
function with regular expressions.您可以将 jq 的
capture
function 与正则表达式一起使用。
jq '[.[] | capture("(?<captured>app-[0-9]+\\.[0-9]+\\.[0-9]+)") | .[]]'
Try it out on jq playground .在 jq 操场上试一试。
Documentation: https://stedolan.github.io/jq/manual/#RegularexpressionsPCRE文档: https://stedolan.github.io/jq/manual/#RegularexpressionsPCRE
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