[英]converting json++ implementation to use rapidJSON: handling mixture of string and wstring
I'm converting some code that originally used the json++ library to now use rapidJSON.我正在将一些最初使用 json++ 库的代码转换为现在使用 rapidJSON。 The code serializes and de-serializes various objects using json files.
该代码使用 json 文件对各种对象进行序列化和反序列化。 In json++, it looks something like this:
在 json++ 中,它看起来像这样:
serialize:连载:
string normal = "normal";
wstring wide = L"wide";
JSON::Object json;
json["normal"] = normal;
json["wide"] = wide;
de-serialize:反序列化:
string normalCopy = json["normal"].as_string();
wstring wideCopy = json["wide"].as_wstring();
I haven't found a simple way to serialize and deserialize mixed strings using rapidJSON.我还没有找到一种使用 rapidJSON 序列化和反序列化混合字符串的简单方法。
Here are two examples:这里有两个例子:
#include <rapidjson/document.h>
#include <rapidjson/writer.h>
#include <iostream>
#include <sstream>
using namespace std;
using namespace rapidjson;
int main()
{
string normalstr = "This is a normal string";
wstring widestr = L"This is a wide string";
Document doc;
auto& alloc = doc.GetAllocator();
Value val(kObjectType);
val.AddMember("normal", normalstr, alloc);
val.AddMember("wide", widestr, alloc); // <-- cannot convert
StringBuffer buffer;
Writer<StringBuffer> writer(buffer);
val.Accept(writer);
ostringstream jsonOutput;
jsonOutput << buffer.GetString();
cout << jsonOutput.str() << endl;
}
and和
#include <rapidjson/document.h>
#include <rapidjson/writer.h>
#include <iostream>
#include <sstream>
using namespace std;
using namespace rapidjson;
int main()
{
string normalstr = "This is a normal string";
wstring widestr = L"This is a wide string";
Document doc;
auto& alloc = doc.GetAllocator();
GenericValue<UTF16<> > val(kObjectType);
val.AddMember(L"normal", normalstr, alloc); // <-- cannot convert
val.AddMember(L"wide", widestr, alloc);
GenericStringBuffer<UTF16<> > buffer;
Writer<GenericStringBuffer<UTF16<> >, UTF16<>> writer(buffer);
val.Accept(writer);
ostringstream jsonOutput;
jsonOutput << buffer.GetString();
cout << jsonOutput.str() << endl;
}
Based on my understanding, RapidJSON is set up to work either exclusively with std::string (UTF-8) or with std::wstring (UTF-16) when dealing at object-level granularity.根据我的理解,RapidJSON 设置为在处理对象级粒度时专门与 std::string (UTF-8) 或 std::wstring (UTF-16) 一起使用。
Do I need to convert from wstring to string when I have both types in the object I want to serialize or is there something available in the API that I'm not aware of?当我想要序列化的 object 中有两种类型时,我是否需要从 wstring 转换为字符串,或者 API 中是否有我不知道的可用内容?
I think you need to use conversion here, I have go through the doc and src of RapidJSON, and confirmed that we can't mix GenericValue
with Value
.我认为您需要在这里使用转换,我通过 RapidJSON 的 doc 和 src 有 go ,并确认我们不能将
GenericValue
与Value
混合。
We can use the wstring_convert
, see this answer as the reference.我们可以使用
wstring_convert
,将此答案作为参考。
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