[英]Why does the output of cout << *lkop[4] is a 0?
So, i wrote this code:所以,我写了这段代码:
int arr[10] = {0,1,2,3,4,5,6,7,8,9};
int (*lkop)[10] = &arr;
cout << *lkop[4];
I was expecting an int 4 to show up, but the output is a 0;我期待一个 int 4 出现,但 output 是 0; Why is that happening, iam really confused.Any ideas?
为什么会这样,我真的很困惑。有什么想法吗? Thank u in advance.
提前谢谢你。
The []
operator has higher precedence than the *
operator. []
运算符的优先级高于*
运算符。
lkop[4]
is out-of-range because arr
, which lkop
points, has only one element of int[10]
. lkop[4]
超出范围,因为lkop
指向的arr
只有一个int[10]
元素。
To do dereferencing first, you should add parenthesis: cout << (*lkop)[4];
要首先进行取消引用,您应该添加括号:
cout << (*lkop)[4];
. .
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