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如何运行 python 列表中的每个字符串? (os.startfile)

[英]How do I run every string in a list in python? (os.startfile)

I want to run every file in a list with os.startfile() but I have no clue how to do it and haven't messed with arrays much.我想用 os.startfile() 运行列表中的每个文件,但我不知道该怎么做,也没有弄乱 arrays 太多。 I've tried 'os.startfile(list)' but that doesn't seem to work.我试过 'os.startfile(list)' 但这似乎不起作用。 Does anyone know how?有谁知道怎么做?

List example:列表示例:

list = ['C:\Programme Files\example1.exe', 'C:\Programme Files\example2.exe', 'C:\Programme Files\example3.exe', ]
for path in list:
    os.startfile(path)

Also, you might want to change 'list' to a different name, because IDE's usually highlight the word list, which makes it look weird.此外,您可能希望将“列表”更改为不同的名称,因为 IDE 通常会突出显示单词列表,这使它看起来很奇怪。

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