[英]How to recode dot to NA in R?
I have a data set where missing values have been coded with a dot.我有一个数据集,其中缺失值已用点编码。 I would like to have missing values blank (NA).我想将缺失值留空(NA)。
Here is the data frame:这是数据框:
df <- data.frame(ITEM1 = c(6, 8, '.'),
ITEM2 = c(1, 6, 9),
ITEM3 = c(4, 2, 5),
ITEM4 = c('.', 3, 2),
ITEM5 = c(1, 6, 9)
)
df
ITEM1 ITEM2 ITEM3 ITEM4 ITEM5
1 6 1 4 . 1
2 8 6 2 3 6
3 . 9 5 2 9
>
The columns will be character
class because of the presence of .
character
.
. . Create a logical matrix
with ==
and assign those elements to NA
, then convert the data.frame columns to its appropriate type with type.convert
使用==
创建一个逻辑matrix
并将这些元素分配给NA
,然后使用type.convert
将 data.frame 列转换为其适当的类型
df[df == "." & !is.na(df)] <- NA
df <- type.convert(df, as.is = TRUE)
Or in a single step with replace
(which internally does the assignment)或者在一个步骤中使用replace
(在内部进行分配)
df <- type.convert(replace(df, df == "." & !is.na(df), NA), as.is = TRUE)
Or another approach is或者另一种方法是
df[] <- lapply(df, function(x) replace(x x %in% '.', NA))
df <- type.convert(df, as.is = TRUE)
Generally, this can be avoided all together, while reading the data itself ie specify na.strings = "."
通常,这可以一起避免,同时读取数据本身,即指定na.strings = "."
in read.csv/read.table
etc.在read.csv/read.table
等
You could use the na_if
function from dplyr
.您可以使用na_if
中的 na_if dplyr
。 Note that the dot changes the type of your columns to be char
which might not be what you want afterwards!请注意,点会将列的类型更改为char
,这可能不是您以后想要的! The following code finds all char
columns, replaces .
以下代码查找所有char
列,替换.
with NA
and converts the column to be numeric:使用NA
并将列转换为数字:
df <- df %>%
mutate(across(where(is.character), ~as.numeric(na_if(., "."))))
Here is an alternativ with set_na
from sjlabelled
package.这是来自sjlabelled
package 的set_na
的替代方案。 Note the columns will remain as character type.请注意,这些列将保留为字符类型。
library(sjlabelled)
set_na(df, na = ".", as.tag = FALSE)
Output: Output:
ITEM1 ITEM2 ITEM3 ITEM4 ITEM5
1 6 1 4 <NA> 1
2 8 6 2 3 6
3 <NA> 9 5 2 9
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