如何使用 python 在条件语句中执行脚本

Question

I am looking to execute the script within an conditional statement, I have also tried to use the script within an function but its not working

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

df1 = pd.read_excel(open(r'input.xlsx', 'rb'), sheet_name='sheet1')
df2 = pd.read_excel(open(r'input.xlsx', 'rb'), sheet_name='sheet2')

if df1['id_number'] != NaN:
  cross = df1[['id_number']].merge(df2[['identity_no']], how='cross')
  cross['match_acc'] = cross.apply(lambda x: fuzz.ratio(x.id_number, x.identity_no), axis=1)
  df1['match_acc'] = df1.id_number.map(cross.groupby('id_number').match_acc.max()) 

Is there any other way to execute the script under the given condition. Can we use the conditional statement by creating an function.

def conn(x):
  cross = df1[['id_number']].merge(df2[['identity_no']], how='cross')
  cross['match_acc'] = cross.apply(lambda x: fuzz.ratio(x.id_number, x.identity_no), axis=1)
  df1['match_acc'] = df1.id_number.map(cross.groupby('id_number').match_acc.max()) 

Please Suggest.

Answer 1

In if df1['id_number']:= NaN: you are comparing a series to a single value (scalar) of NaN . This will create a boolean array of True / False values. You need to specify whether you want any of those values to be True , or all of the values:

if df1['id_number'].notna().any(): # any one value has to be != NaN

or

if df1['id_number'].notna().all(): # all have to be != NaN