按另一个对象的值过滤对象数组

Question

I would like to filter an array of objects based on the values in another object. I am trying to map() the array and filter() inside the function so that I am able to get a new array with only the desired (active) fields.

I am trying to get the filter on the Object.entries() , I try to compare the keys and check if the values of the active filters are true , but I am not getting it right.

 const records = [ { id: 1, name: "first", date: "05/02" }, { id: 2, name: "second", date: "06/02" }, { id: 3, name: "third", date: "07/02" }, { id: 4, name: "fourth", date: "08/02" } ]; const active = { id: true, name: false, date: true }; const result = records.map((record) => { return Object.entries(record).filter((entry) => { Object.entries(active).forEach((activeEntry) => { return activeEntry[1] && activeEntry[0] === entry[0]; }); }); }); console.log(result);

This is the desired outcome

const desiredOutcome = [
  {
    id: 1,
    date: "05/02"
  },
  {
    id: 2,
    date: "06/02"
  },
  {
    id: 3,
    date: "07/02"
  },
  {
    id: 4,
    date: "08/02"
  }
];

Answer 1

You can filter over the entries of the object and convert it back to an object with Object.fromEntries .

 const records=[{id:1,name:"first",date:"05/02"},{id:2,name:"second",date:"06/02"},{id:3,name:"third",date:"07/02"},{id:4,name:"fourth",date:"08/02"}]; const active = { id: true, name: false, date: true }; const res = records.map(x => Object.fromEntries( Object.entries(x).filter(([k])=>active[k]))); console.log(res);

Answer 2

Simply filter the keys by the key existing and then use Object.fromEntries to go back to an object

 const records = [ { id: 1, name: "first", date: "05/02" }, { id: 2, name: "second", date: "06/02" }, { id: 3, name: "third", date: "07/02" }, { id: 4, name: "fourth", date: "08/02" } ]; const active = { id: true, name: false, date: true }; const result = records.map((record) => { return Object.fromEntries( Object.entries(record).filter(([key,value]) => active[key])); }); console.log(result);