简体   繁体   English

如何将数组字典数组转换为 pandas dataframe?

[英]How to convert array of dictionary of array to pandas dataframe?

I have an array of nested dictionary:我有一个嵌套字典数组:

data = {"A":"a","B":"b","ID":[{"ii":"ABC","jj":"BCD"},{"ii":"AAC","jj":"FFD"}],"Finish":"yes"}数据 = {"A":"a","B":"b","ID":[{"ii":"ABC","jj":"BCD"},{"ii":"AAC" ,"jj":"FFD"}],"完成":"是"}

I used,我用了,

res = pd.DataFrame.from_dict(data , orient='index')

But the ID is still returned as list of dictionary.但是 ID 仍然作为字典列表返回。

A  B      ID                                              Finish
a  b  [{"ii":"ABC","jj":"BCD"},{"aa":"AAC","bb":"FFD"}]    yes

But I want everything to be converted to df.但我希望所有内容都转换为 df。 Not sure how to do it.不知道该怎么做。 Kindly help.请帮忙。

Expected Output:预期 Output:

A  B  ID.ii  ID.jj   Finish
a  b   ABC    BCD      yes
a  b   AAC    FFD      yes

You can achieve this using pandas json_normalize您可以使用 pandas json_normalize实现此目的

df = pd.json_normalize(data, meta=['A', 'B'], record_path=['ID'], record_prefix="ID.")

Output Output

  ID.ii ID.jj  A  B
0   ABC   BCD  a  b
1   AAC   FFD  a  b

record_path - will be used to flatten the specific key record_prefix - is added as a column prefix meta - is the columns that needs to be preserved without flattening record_path - 将用于展平特定键 record_prefix - 添加为列前缀 meta - 是需要保留而不展平的列

Refer the documentation for examples有关示例,请参阅文档

To achieve this without using json_normalize , you can pre-process the input like this-要在不使用json_normalize的情况下实现这一点,您可以像这样预处理输入 -

data = {"A":"a","B":"b","ID":[{"ii":"ABC","jj":"BCD"},{"ii":"AAC","jj":"FFD"}],"Finish":"yes"}
op = {}

for i in data:
    if isinstance(data[i], list):
        for j in data[i]:
            for k in j:
                tmp = str(i)+"."+str(k)
                if tmp not in op:
                    op[tmp] = [j[k]]
                else:
                    op[tmp].append(j[k])
    else:
        op[i] = data[i]

        
>>> data
{'A': 'a', 'B': 'b', 'ID': [{'ii': 'ABC', 'jj': 'BCD'}, {'ii': 'AAC', 'jj': 'FFD'}], 'Finish': 'yes'}
>>> op
{'A': 'a', 'B': 'b', 'ID.ii': ['ABC', 'AAC'], 'ID.jj': ['BCD', 'FFD'], 'Finish': 'yes'}

After this you can directly use之后就可以直接使用

>>> pd.DataFrame(op)

   A  B ID.ii ID.jj Finish
0  a  b   ABC   BCD    yes
1  a  b   AAC   FFD    yes

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM