[英]Nested libcurl request c++
My question would be how would I do a nested curl request because my current code is this and does not work.我的问题是我将如何执行嵌套的 curl 请求,因为我当前的代码是这个并且不起作用。 I does not work as I can see the requests going to my server and there is only one which is a GET request.
我不工作,因为我可以看到请求发送到我的服务器,并且只有一个是 GET 请求。
#include <curl/curl.h>
#include <iostream>
int rad = rand() % 100000;
std::string agent_name = "https://127.0.0.1:443/agent/" + std::to_string(rad);
int main(int argc, char *argv[])
{
CURLcode res;
CURL *curl;
curl = curl_easy_init();
curl_easy_setopt(curl, CURLOPT_BUFFERSIZE, 102400L);
curl_easy_setopt(curl, CURLOPT_URL, "https://127.0.0.1:443/");
curl_easy_setopt(curl, CURLOPT_NOPROGRESS, 1L);
curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L);
curl_easy_setopt(curl, CURLOPT_FTP_SKIP_PASV_IP, 1L);
curl_easy_setopt(curl, CURLOPT_TCP_KEEPALIVE, 1L);
res = curl_easy_perform(curl);
if (res == CURLE_OK) {
long response_code;
curl_easy_getinfo(curl, CURLINFO_RESPONSE_CODE, &response_code);
if (response_code == 200)
{
std::cout << "Hello";
CURLcode ret;
CURL *hnd;
hnd = curl_easy_init();
curl_easy_setopt(hnd, CURLOPT_BUFFERSIZE, 102400L);
curl_easy_setopt(hnd, CURLOPT_URL, agent_name);
curl_easy_setopt(hnd, CURLOPT_NOPROGRESS, 1L);
curl_easy_setopt(hnd, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(hnd, CURLOPT_SSL_VERIFYHOST, 0L);
curl_easy_setopt(hnd, CURLOPT_CUSTOMREQUEST, "POST");
curl_easy_setopt(hnd, CURLOPT_FTP_SKIP_PASV_IP, 1L);
curl_easy_setopt(hnd, CURLOPT_TCP_KEEPALIVE, 1L);
ret = curl_easy_perform(hnd);
curl_easy_cleanup(hnd);
hnd = NULL;
}
else { }
}
curl_easy_cleanup(curl);
curl = NULL;
}
This prints Hello to stdout but does not run the curl POST request, so How would one do a nested curl request.这会将 Hello 打印到标准输出,但不会运行 curl POST 请求,因此如何执行嵌套的 curl 请求。
EDIT: I tried removing the if statement.编辑:我尝试删除 if 语句。 So my question is how does one do two libcurl requests
所以我的问题是如何做两个 libcurl 请求
Your curl_easy_perform(hnd)
returns 3
:您的
curl_easy_perform(hnd)
返回3
:
CURLE_URL_MALFORMAT (3) CURLE_URL_MALFORMAT (3)
The URL was not properly formatted. URL 的格式不正确。
You will have to pass a char *
instead of a std::string
(see here ):你将不得不传递一个
char *
而不是std::string
(见这里):
curl_easy_setopt(hnd, CURLOPT_URL, agent_name.c_str());
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