在 switch 语句中，如果没有给出 break，为什么所有语句都在 true 语句之后执行？

Question

In a switch / case statement, the case statements is for checking the condition, so why should it execute the statements which are false? Even if it continues execution of all the cases up to the end of the program if break is not given, won't the case statement check the condition. Isn't its internal working same as if / else statements? If not, then how does it work internally? Language: C

Answer 1

No, a case label (which isn't a statement) doesn't check any condition. In fact it doesn't do anything at all (notice how you can have multiple cases in a row?) and doesn't produce any code. Upon entering the switch, execution jumps to the matching case. And that's it. Once you're in the block, the labels don't do anything, but a break will get you out.