删除对象数组中的特定元素

Question

I have an Array of Object that is declared and look like this in Groovy:

def meal = [['Apple','Tomatoes', 'Coffee'],['Peach','Broccoli', 'Water'],['Orange','Peas', 'Pepsi'],['Banana','Beans', 'Coffee']]

How could I remove the third element in each object to my output look like this:

def meal = [['Apple','Tomatoes'],['Peach','Broccoli'],['Orange','Peas'],['Banana','Beans']]

I tried this but it returns a boolean (true)

def removeValue = meal.remove{a ->
a[2]
a}

Answer 1

def meal = [['Apple','Tomatoes', 'Coffee'],['Peach','Broccoli', 'Water'],['Orange','Peas', 'Pepsi'],['Banana','Beans', 'Coffee']]

meal.remove(meal[2])

println(meal) \ [[Apple, Tomatoes, Coffee], [Peach, Broccoli, Water], [Banana, Beans, Coffee]]

remove method creates a copy of given list without given index or condition(for closure) value

Answer 2

dropRight and splicing and maybe others can be used to get rid of elements at the end of a vector and give you back a new vector. Using the Spread-Operator *. to do that on all.

meal*.dropRight(1)

If you prefer modifying your original, there is also removeLast .