将 sys.argv 转换为位置 argparse 参数？

Question

I have a script that currently takes both sys.argv and argparse arguments. I need to change the sys.argv input into a positional argparse argument. How would I do this?

Script (irrelevant sections omitted):

import sys
import argparse
from pathlib import Path

parser = argparse.ArgumentParser()

parser.add_argument("-ru", "--remove-unparsable", dest="remove_unparsable",
                    action="store_true",
                    help="When this option is enabled, unparsable fonts are "
                         "removed instead of ignored")

args, unknown = parser.parse_known_args()

def handle_path(path: Path):
    if path.stem.startswith("."):
        return
    if path.is_dir():
        for f in path.iterdir():
            handle_path(f)
    else:
        handle_file(path)

def main():
    if len(sys.argv) == 1:
        print(f"Usage: {sys.argv[0]} [<files>]")
    else:
        for path in sys.argv[1:]:
            if not path.startswith("-"):
                handle_path(Path(path))


if __name__ == "__main__":
    main()

Answer 1

You could do the following:

def main():
    parser = argparse.ArgumentParser()
    
    parser.add_argument("-ru", "--remove-unparsable", dest="remove_unparsable",
                        action="store_true",
                        help="When this option is enabled, unparsable fonts are "
                        "removed instead of ignored")
    parser.add_argument("files", nargs="+")
    args, unknown = parser.parse_known_intermixed_args()
    for path in args.files:
        handle_path(Path(path))

Here, ArgumentParser.parse_known_intermixed_args handles the positional files argument, which can be intermixed with named arguments such as -ru and unknown arguments. The nargs="+" parameter specifies that at least one file must be present.