[英]Swift generic Serializable protocol
I noticed that I have a lot of repeated code for getting/sending JSON to my app's API, but the only thing that is different is what entity is being (de)serialized.我注意到我有很多重复的代码用于获取/发送 JSON 到我的应用程序的 API,但唯一不同的是正在(反)序列化的实体。 So I came up with the following design (for brevity only the GET method):
所以我想出了以下设计(为简洁起见,只有 GET 方法):
HTTPClient.swift HTTPClient.swift
func getEntityJSON<T: JSONSerializable>(
type: T.Type,
url: String,
completionHandler: @escaping (_ result: T?,
_ headers: [String: String]?,
_ statusCode: Int?,
_ error: Error?) -> Void) {
HttpClient.sharedInstance().getJSON(url, completionHandler: { (jsonData, headers, statusCode, error) in
if let error = error {
completionHandler(nil, headers, statusCode, error)
} else {
if let entityData = jsonData {
completionHandler(T.fromJSON(data: entityData), headers, statusCode, nil)
}
}
})
}
to intend to use it like this:打算像这样使用它:
HTTPClient.sharedInstance().getEntity(type: Translation, url: url) { (translation, _, _, _) in
// do stuff with Translation instance
}
and here is the JSONSerializable
protocol:这是
JSONSerializable
协议:
import Foundation
import SwiftyJSON
protocol Serializable: Codable {
static func deserialize<T: Codable>(data: Data) -> T?
func serialize() -> Data?
}
extension Serializable {
static func deserialize<T: Decodable>(data: Data) -> T? {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
decoder.dateDecodingStrategy = .formatted(DateFormatter.iso8601Full)
return try? decoder.decode(T.self, from: data)
}
func serialize() -> Data? {
let encoder = JSONEncoder()
encoder.keyEncodingStrategy = .convertToSnakeCase
encoder.dateEncodingStrategy = .formatted(DateFormatter.iso8601Full)
return try? encoder.encode(self)
}
}
protocol JSONSerializable: Serializable {
func toJSON() -> JSON?
static func fromJSON<T>(data: JSON) -> T?
}
extension JSONSerializable {
func toJSON() -> JSON? {
if let data = self.serialize() {
return try? JSON(data: data)
} else {
return nil
}
}
}
This allows me to define a struct like this:这允许我定义一个这样的结构:
Translation.swift翻译.swift
struct Translation: Hashable, Identifiable, JSONSerializable {
var id: UUID
...
static func fromJSON(data: JSON) -> Translation? {
and I will get serialize, deserialize, toJSON
functions.我将获得
serialize, deserialize, toJSON
函数。 But the compiler complains that Translation
does not conform to JSONSerializable
, due to lack of:但是编译器抱怨
Translation
不符合JSONSerializable
,因为缺少:
static func fromJSON<T>(data: JSON) -> T?
. . I thought I would be able to implement that function with a concrete type,
Translation
in this case.我想我可以用一个具体的类型来实现 function,在这种情况下是
Translation
。
I would like to be both able to do Translations.fromJSON(data: data)
as well as T.fromJSON(data: data)
.我希望能够同时执行
Translations.fromJSON(data: data)
和T.fromJSON(data: data)
。 How can I achieve this?我怎样才能做到这一点?
Generics ( <T>
) means that your method can work with any type that the caller (not the callee, not the implementer, not anyone else) specifies. Generics (
<T>
) 意味着您的方法可以使用调用者(不是被调用者,不是实现者,不是其他任何人)指定的任何类型。 In the case of fromJSON
, this is clearly not the case.在
fromJSON
的情况下,显然不是这样。 Any concrete implementation of fromJSON
only works with T
being the enclosing type, so fromJSON
is not suitable to be generic. fromJSON
的任何具体实现仅适用于T
作为封闭类型,因此fromJSON
不适合泛型。
When a method "only works with T
being the enclosing type", it is the use case of Self
types:当方法“仅适用于
T
作为封闭类型”时,它是Self
类型的用例:
protocol JSONSerializable: Serializable {
func toJSON() -> JSON?
static func fromJSON(data: JSON) -> Self?
}
This way, your Translation
implementation would conform to the protocol.这样,您的
Translation
实现将符合协议。
Similarly, deserialise
should also be declared as:同样,
deserialise
也应该声明为:
static func deserialize(data: Data) -> Self?
If you actually want a JSONSerialisable
that can turn JSON
into any type that the caller wants, then it's less of a JSONSerialisable
, and more of a JSONSerialiser
, and it doesn't make much sense to inherit from Codable
in that case.如果您确实想要一个
JSONSerialisable
可以将JSON
转换为调用者想要的任何类型,那么它不是JSONSerialisable
,而是更多JSONSerialiser
,在这种情况下从Codable
继承没有多大意义。
OK I ended up implementing a JSONSerializer
, because I couldn't get it to work for collections of items to be (de)serialized.好的,我最终实现了
JSONSerializer
,因为我无法让它为 collections 的要(反)序列化的项目工作。 This is how it currently looks:这是它目前的样子:
import Foundation
import SwiftyJSON
protocol JSONSerializable {
static func fromJSON(data: JSON) -> Self?
}
class JSONSerializer {
static func deserialize<T: Decodable>(_ type: T.Type, data: Data) -> T? {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
decoder.dateDecodingStrategy = .formatted(DateFormatter.iso8601Full)
return try? decoder.decode(type, from: data)
}
static func serialize<T: Encodable>(_ object: T) -> Data? {
let encoder = JSONEncoder()
encoder.keyEncodingStrategy = .convertToSnakeCase
encoder.dateEncodingStrategy = .formatted(DateFormatter.iso8601Full)
return try? encoder.encode(object)
}
static func fromJSON<T: JSONSerializable>(type: T.Type, data: JSON) -> T? {
T.fromJSON(data: data)
}
static func toJSON<T: Encodable>(_ object: T) -> JSON? {
if let data = Self.serialize(object) {
return try? JSON(data: data)
} else {
return nil
}
}
}
I will look into the fromJSON
function later to see if I can completely get rid of JSONSerializable
and implemented it in the JSONSerializer
like this:稍后我将研究
fromJSON
function 看看我是否可以完全摆脱JSONSerializable
并在JSONSerializer
中实现它,如下所示:
static func fromJSON<T: Decodable>(type: T.Type, data: JSON) -> T? {
if let jsonData = try? data.rawData() {
return Self.deserialize(type, data: jsonData)
}
return nil
}
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