[英]cooldown format discord.py
I didn't where to ask so I will ask here.我没有在哪里问,所以我会在这里问。 (Sorry if this os a duplicated question or anything). (对不起,如果这是一个重复的问题或任何东西)。
I have a command that I want to use every 2 hours, which I have done, but the cooldown error is my issue.我有一个命令,我想每 2 小时使用一次,我已经完成了,但是冷却错误是我的问题。 I want to format it like: 1 hour, 30 mins.我想将其格式化为:1 小时 30 分钟。 I have tried this but it does the hours in minutes and minutes in seconds.我已经尝试过了,但它以分钟为单位,以秒为单位。
@command.error
async def command_error(self, ctx, error):
if isinstance(error, commands.CommandOnCooldown):
cd = round(error.retry_after)
hours = str(cd // 3600)
minutes = str(cd % 60)
await ctx.send(f'You can use this command again in {hours} hour(s), {minutes} minute(s)')
I also tried this but it would display like 1.0 hours, 30.0 mins:我也试过这个,但它会显示 1.0 小时,30.0 分钟:
@command.error #thats the name of my command
async def command_error(self, ctx, error):
if isinstance(error, commands.CommandOnCooldown):
m, s = divmod(error.retry_after, 60)
h, m = divmod(m, 60)
d, h = divmod(h, 60)
await ctx.send(f'You can use this command again in {h} hour(s), {m} minute(s)')
Anyone know a fix or something?任何人都知道修复或什么? Any help is appreciated:)任何帮助表示赞赏:)
To convert the time you can use something like this:要转换时间,您可以使用以下内容:
def better_time(self, cd:int):
time = f"{cd}s"
if cd > 60:
minutes = cd - (cd % 60)
seconds = cd - minutes
minutes = int(minutes/ 60)
time = f"{minutes}min {seconds}s"
if minutes > 60:
hoursglad = minutes -(minutes % 60)
hours = int(hoursglad/ 60)
minutes = minutes - (hours*60)
time = f"{hours}h {minutes}min {seconds}s"
return time
And to implement it into your code and send the remaining time you can just pass the following:要将其实现到您的代码中并发送剩余时间,您只需传递以下内容:
if isinstance(error, commands.CommandOnCooldown):
cd = round(error.retry_after)
if cd == 0:
cd = 1
await ctx.send(f"**{ctx.author.mention } - Cooldown, try again in** `{self.better_time(cd)}`**.**", delete_after=3)
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