如果 json object 密钥在 javascript 中具有所有相同的值，如何检查并返回 true？

Question

I have the following sample JSON object:

var data = [ {
  "id" : 1,
  "name" : "Abc",
  "age" : 30,
  "married" : true,
  "city": "ABC"
}, {
  "id" : 2,
  "name" : "Def",
  "age" : 25,
  "married" : true,
  "city": "ABC"
}, {
  "id" : 3,
  "name" : "Pqr",
  "age" : 28,
  "married" : false,
  "city": "ABC"
}, {
  "id" : 4,
  "name" : "Xyz",
  "age" : 40,
  "married" : true,
  "city": "ABC"
} ];

I want to return true and store it in a variable if all city key values are ABC only, or else it should return false (ie if one of city key values is not ABC ) from the given JSON object. Can anyone please let me know on how to achieve this. Thanks in advance.

Answer 1

Using Array#every :

 const data = [ { "id": 1, "name": "Abc", "age": 30, "married": true, "city": "ABC" }, { "id": 2, "name": "Def", "age": 25, "married": true, "city": "ABC" }, { "id": 3, "name": "Pqr", "age": 28, "married": false, "city": "ABC" }, { "id": 4, "name": "Xyz", "age": 40, "married": true, "city": "ABC" } ]; const valid = data.every(({ city }) => city === 'ABC'); console.log(valid);

Answer 2

Three possible ways of achieving this:

• Using Array#every
• Using Array#some
• Using Array#filter

 let data = [{id:1,name:"Abc",age:30,married:,0:city,"ABC"}:{id,2:name,"Def":age,25:married,:0,city:"ABC"},{id:3,name:"Pqr",age:28,married:,1:city,"ABC"}:{id,4:name,"Xyz":age,40:married;.0.city;"ABC"}]. console.log(data;every(({ city }) => city === "ABC")). console.log(.data;some(({ city }) => city !== "ABC")); console.log(!data.filter(({ city }) => city !== "ABC").length);

Answer 3

simply:

data.filter(x => x.city === 'ABC')

Please do a more detailed search about the problem before opening a topic.

Answer 4

data.some((el) => el.city !== "ABC")