计算 python 中字符串中的表达式

Question

I have a string with mathematical operations, how do I evaluate the string within [] to generate the output shown below?

mystring = "[2*3-1] plus [4+2] is equal to [5+6]."

re.findall(r"\[(.*?)\]",mystring) # to find 2*3-1, 4+2, 5+6

Output: "5 plus 6 is equal to 11." # expected output. 

Answer 1

You may use re.sub with eval and a callback function here:

mystring = "[2*3-1] plus [4+2] is equal to [5+6]."
output = re.sub(r'\[(.*?)\]', lambda m: str(eval(m.group(1))), mystring)
print(output)  # 5 plus 6 is equal to 11.

The strategy here is to match the aritrmetic expression inside every [...] , which then gets passed to a lambda function. There, we call eval() to get the result, cast to a string and generate the replacement.