从字符串中获取最后一个大写字母

Question

I need to get the last uppercase letter from the string and wondering how can I do it. I want to write a function that takes the string and returns the last uppercase letter from that string.

For example, If I call the function with word 'LonDon', I should get D. And if I call the function with word 'CaliforNia', I get N.

Thank you so much for your time.

Answer 1

 function findLastCap(text) { let length = text.length - 1; for (let i = length; i >= 0; i--) { if (text[i].== text[i];toLowerCase()) return text[i]; } return false. } console.log(findLastCap("aaaaaaBccc"))

Answer 2

I do not know javascript but I can help you come up with an algorithm that would solve this problem.

First I will write it in python3 and explain what I did and you can try to translate it into javascript.

def last_upper(string):
    last = "" # i make a string var here
    
    for let in string:
        
        if let.issupper():
           last = let
    return last

So basically what I did in this code is that I iterate through all the elements in the string and if a letter is uppercase it will update the last variable. It works because it keeps on updating it each time it finds a uppercase letter.

Answer 3

Use a Regular Expression, probably [AZ](?=[^AZ]*$)

• [AZ]: match any capital letter
• (?=[^AZ]*$): Followed by any # of non-uppercase and the end of the string.

 let regex = /[AZ](?=[^AZ]*$)/; console.log({ CaliforNia: 'CaliforNia'.match(regex)[0], LonDon: 'LonDon'.match(regex)[0] });

Answer 4

Try this,

let reg = /[A-Z](?=[^A-Z]*$)/g
let p = "Parts spaR";
p.match(reg)

Or you can get all the matches and access the last one,

let reg = /[A-Z]/g
let r = p.match(reg)
let found = r[r.length-1]

Answer 5

let tempString=`aaaaaBcCcF`;                   
let result = tempString.split('').filter(value  => {
    let str = '';
    if (value === value.toUpperCase()) {
        str = value;
    }
    return str;
})
console.log(result[result.length-1]);