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从两个表更新 sql 表 使用单个查询

[英]update sql table from two tables Using a single query

i want to update a table column by taking i/p from two tables in a single query.我想通过在单个查询中从两个表中获取 i/p 来更新表列。

This is what i have tried.这是我尝试过的。

   $query="UPDATE all_stores a
inner join i_v i on
    a.id = i.child_id
set a.qty = (a.qty-i.qty)";

But this is not updating the table.但这不是更新表格。

Where Table-all_stores is:其中 Table-all_stores 是:



   id-    name         qty -           dec_qty
    1      a1          68                0
    2      b2          32                0
    3      c3          12                0
    4      d4          43                0

And table-i_v is:表 i_v 是:


    id-    name        qty -          child_id
    1      a1          12               1
    2      a2          32               2
    3      a1          11               1
    4      a1          23               1

if I understand correctly, you want to do this:如果我理解正确,你想这样做:

UPDATE all_stores a
set a.qty = (a.qty-(select sum(qty) from i_v i where a.id = i.id))

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