如何从 echo 获取 PHP output 中的换行符？
[英]How do I get a newline in the PHP output from echo?
问题描述
I am generating a large amount of HTML code with PHP using echo and it is all appearing on one line.
我正在使用echo使用 PHP 生成大量 HTML 代码，它们都出现在一行上。
I understand that HTML ignores whitespace, and there are thousands of answers which point out that you need <BR> or a block element.我知道 HTML 会忽略空格，并且有成千上万的答案指出您需要<BR>或块元素。 But that is not my question.但这不是我的问题。
My problem is that is very hard to debug my HTML source code when it is all on one line.我的问题是，当我的 HTML源代码全部在一条线上时，很难调试它。 I am using Windows 7 and the Firefox browser tool Page Source to show the source code .我正在使用 Windows 7 和 Firefox 浏览器工具Page Source来显示源代码。
For a simple example, if the text editor I use shows举个简单的例子，如果我使用的文本编辑器显示
<HTML><BODY>
Hello, World!
</BODY></HTML>
Then the browser source code tool shows exactly that too, and when I generate it with PHP like然后浏览器源代码工具也显示了这一点，当我使用 PHP 生成它时
<?php
echo "<HTML><BODY>";
echo "Hello, World!";
echo "</BODY></HTML>";
?>
then the browser tool shows, as you would expect,然后浏览器工具显示，如您所料，
<HTML><BODY>Hello, World!</BODY></HTML>
I want to break the lines, and have tried我想打破界限，并尝试过
<?php
echo "<HTML><BODY>\n";
echo "Hello, World!\n";
echo "</BODY></HTML>\n";
?>
and with "\r\n" and with "\xA" and also like this和"\r\n"和"\xA"也像这样
<?php
echo "<HTML><BODY>" . PHP_EOL;
echo "Hello, World!" . PHP_EOL;
echo "</BODY></HTML>" . PHP_EOL;
?>
yet the content stays resolutely on a single line.但是内容坚决地保持在一行上。
1 个解决方案
解决方案1
1 2021-05-15 11:43:00
This works on windows这适用于 windows
<?php
echo "<HTML><BODY>
";
echo "Hello, World!
";
echo "</BODY></HTML>
";
?>
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