向代码提供输入时出现 EOF 错误

Question

I tried a problem from SPOJ called The next palindrome. The problem statement is given as

A positive integer is called a palindrome if its representation in the decimal system is the same when read from left to right and from right to left. For a given positive integer K of not more than 1000000 digits, write the value of the smallest palindrome larger than K to output. Numbers are always displayed without leading zeros.

Here is my code

def palindrome(n):
    return True if n[::-1] == n else False

t = int(input())
for i in range(t):
    li = []
    n = input()
    for j in range(int(n) + 1, 1000000 + 1):
        if palindrome(str(j)) == True:
            li.append(j)
    print(li[0])

I tried giving an input like this

1
1000000

I am getting an error like this

Traceback (most recent call last):
  File "./prog.py", line 7, in <module>
EOFError: EOF when reading a line

Answer 1

The error is caused because your input "n" makes both arguments same in the range function in this line "for j in range(int(n) + 1, 1000000 + 1)". It looks like this range(1000001, 1000001) which return nothing. Use input of "n" smaller than 1000000. It will work.

It return empty list when I use this code.

n = 1000000
print(list(range(int(n) +1, 1000000+1)))

That why there is no data in it. EOF error is caused when python doesn't read any data.