python：从元组列表中删除列表括号

Question

I apologise if there are dupes. I've only found codes that remove tuples from list, but not the list itself. I have a constant

a = [[(1,2,3),(3,2,1)], [(2,1,6),(7,3,2),(1,0,2)]]

And I'd like to remove all the brackets inside a so it becomes

a = (1,2,3),(3,2,1),(2,1,6),(7,3,2),(1,0,2)

Is it possible to do it in a simple way? I've tried something similar to

for i in a:
    print(a[0], a[1], a[2])

but the number of tuples in each interior list vary, so I can't just use [0] etc..

Answer 1

IIUC, try chain.from_iterable

from itertools import chain

print([i for i in chain.from_iterable(a)])

---

[(1, 2, 3), (3, 2, 1), (2, 1, 6), (7, 3, 2), (1, 0, 2)]

Answer 2

One possible way to this is by using reduce .

>>> from functools import reduce
>>> reduce(lambda a,b : tuple(a+b),a)
((1, 2, 3), (3, 2, 1), (2, 1, 6), (7, 3, 2), (1, 0, 2))

Answer 3

a = [[(1,2,3),(3,2,1)], [(2,1,6),(7,3,2),(1,0,2)]]

for _list in a:
    for _tuple in _list:
        print(_tuple)

Answer 4

Use list comprehension, however, you will get of list of tuples, for what you've mentioned in the desired output, you need to unpack the tuples with the same number of variables:

a = [x for l in a for x in l]

Output:

[(1, 2, 3), (3, 2, 1), (2, 1, 6), (7, 3, 2), (1, 0, 2)]