您如何在运行时比较具有不同属性的对象？

Question

My code structure is something like this

class Drawing()
{
ObjectType = "Drawing";
}

class Shape() : Drawing()
{
DrawingType = "Shape";
}

class square() : Shape()
{
ShapeType = "square";
}

class circle() : Shape()
{
ShapeType = "circle";
}

class triangle() : Shape()
{
ShapeType = "triangle";
}

class lines() : Drawing()
{
DrawingType = "lines";
}

class horizontal() : lines()
{
linesType = "horizontal";
}

class vertical() : lines()
{
linesType = "vertical";
}

etc...

I am trying to figure out the right logic in how to solve this problem so the picture is a simple representation of what I have.

I have a object structure of something like in the picture where they're all inheriting the level above them. They all have properties of its type. They would all have ObjectType, and the 2nd level has DrawingType, and the 3rd level has either ShapeType, LineType, or PointType...

So for example, square would have

square {
ObjectType = "drawing";
DrawingType = "shapes";
ShapeType = "square"
} 

However, vertical would have different properties

vertical {
    ObjectType = "drawing";
    DrawingType = "lines";
    LineType = "vertical"
    } 

Now my problem is, lets say I wanted a user to select something based on their input, how would i do it? Like lets say the user typed "square", how would I select square? It would be easy if the properties were the same cause I could just compare them. But how would I do it with a structure like this?

Answer 1

As these all classes are derived from one base class hence all the child classes contains the property coming from parents. Object level comparison will lead you comparison of one Drawing object to another as all the objects are derived from there only. Hence i have implemented IComparer to get your desired result ->

Here is the code ->>

Main Class :

Drawing drawing1 = new Drawing();
        Drawing drawing2 = new Drawing();
        drawing2.ObjectType = "newdrawing";

        Shape shape = new Shape();
        triangle triangle1 = new triangle();
        triangle triangle2 = new triangle();
        triangle2.ShapeType = "another";

        //all -1 is not equals and 0 is equals
        int result1 = drawing1.Compare(drawing1, drawing2);
        int result2 = drawing1.Compare(drawing1, drawing1);

        int result3 = drawing1.Compare(drawing1, shape);
        int result4 = shape.Compare(shape, triangle1);

        int result5 = triangle1.Compare(triangle1, triangle2);

Other classes :

public class Drawing : IComparer
{
    public string ObjectType { get; set; } = "Drawing";

    public int Compare(object x, object y)
    {
        //returning 0 is equals
        if (x.GetType().Name == y.GetType().Name)
        {
            switch (x.GetType().Name)
            {
                case "Drawing":
                    return ((Drawing)x).ObjectType == ((Drawing)y).ObjectType ? 0 : -1;
                case "Shape":
                    return ((Shape)x).DrawingType == ((Shape)y).DrawingType ? 0 : -1;
                case "square":
                    return ((square)x).ShapeType == ((square)y).ShapeType ? 0 : -1;
                case "triangle":
                    return ((triangle)x).ShapeType == ((triangle)y).ShapeType ? 0 : -1;
                default:
                    return -1; // Not equal
            }
        }
        return -1; // Not equal
    }
}

class Shape : Drawing
{
    public string DrawingType { get; set; } = "Shape";

}

class square : Shape
{
    public string ShapeType { get; set; } = "square";
}

class circle : Shape
{
    public string ShapeType { get; set; } = "circle";
}

class triangle : Shape
{
    public string ShapeType { get; set; } = "triangle";
}

class lines : Drawing
{
    public string DrawingType { get; set; } = "lines";
}

class horizontal : lines
{
    public string linesType { get; set; } = "horizontal";
}

class vertical : lines
{
    public string linesType { get; set; } = "vertical";
}

Hope this will work for you. please write back with you code snippet specifically not working. Cheers