[英]flask-apispec not populating kwargs with values from GET query (implementation of example code from documentation)
I am using flask-apispec
with webargs
to define the types of a simple API. I have produced a minimal example, below, that reproduces the issue, which is that the kwargs
object is empty.我正在使用带有
webargs
的flask-apispec
来定义一个简单的 API 的类型。我在下面制作了一个最小的例子,它重现了这个问题,即kwargs
object 是空的。
Server code:服务器代码:
import flask
from flask_apispec import use_kwargs
from webargs import fields
app = flask.Flask(__name__)
@app.route('/pets', methods=["GET"])
@use_kwargs({'species': fields.Str()})
def list_pets(**kwargs):
assert False, kwargs # NO DATA HERE
if __name__ == "__main__":
app.run(host="0.0.0.0", port=5000)
Simple client script:简单的客户端脚本:
import requests
requests.get("http://localhost:5000/pets", params={"species": "cat"})
Why is the kwargs
dict empty?为什么
kwargs
字典是空的? I don't see how the above is at all different from the example in the flask-apispec documentation.我看不出上面的内容与 flask-apispec 文档中的示例有何不同。
I had the same problem and suffered a little with the documentation.我遇到了同样的问题,并且在文档方面遇到了一些问题。
Referencing webargs docs (that is what I understood flask-apispec
uses under the hood) I found some examples and was able to implement it.参考webargs 文档(这是我所理解
flask-apispec
在幕后使用的内容)我找到了一些示例并能够实现它。
The location
parameter is what was missing.缺少
location
参数。 In your example it would be:在您的示例中,它将是:
@app.route('/pets', methods=["GET"])
@use_kwargs({'species': fields.Str()}, location="query")
def list_pets(**kwargs):
print(kwargs) # Now "species" should be here if sent through the query
I'm using flask-apispec v0.11.1
, which installed webargs v8.1.0
on my system.我正在使用
flask-apispec v0.11.1
,它在我的系统上安装了webargs v8.1.0
。
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