如何用同一个对象（NSString）填充整个 NSMutableArray

Question

I'm trying this, but it looks like it's not right, are there any options? Thank you

NSMutableArray *copyy = [[NSMutableArray alloc] initWithCapacity:8];
for (int i = 1; i < copyy.count; i++) {
    NSString *str = @"test";
    [copyy addObject:[str copy][i]];
}

Answer 1

You can write a simple category on top of the NSArray like:

@interface NSArray(Repeating)
+ (NSArray*)arrayByRepeatingObject:(id)object times:(NSUInteger)t;
@end

@implementation NSArray(Repeating)
+ (NSArray*)arrayByRepeatingObject:(id)object times:(NSUInteger)t {
    id objects[t];
    for(NSUInteger i=0; i<t; ++i) objects[i] = object;
    return [NSArray arrayWithObjects:objects count:t];
}
@end

so you can build an array by repeating an object like:

NSArray * items = [NSArray arrayByRepeatingObject:@"test" times:8];

Note: if you want a mutable version, just ask for a mutableCopy :

NSMutableArray * mutableItems = items.mutableCopy;