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DB2 从审计表中获取最新修改值和先前值

[英]DB2 Get latest modified and previous value from audit table

I have a audit table, i am trying to get the current and previous value for a column(rank) with audit timestamp information.我有一个审计表,我正在尝试使用审计时间戳信息获取列(排名)的当前值和先前值。 I would like to get the timestamp when the value was changed.我想获取值更改时的时间戳。 Eg:例如: 在此处输入图像描述

For id = 1 , rank was latest changed from 3 to 5 on 13-05-2021 14:10 by userid = 2 .对于id = 1 ,排名最近在 2021 年 5 月13-05-2021 14:10userid = 2 from 3 to 5更改为 5。 I have written below query it gives the current and previous modified value but it gives the latest date and userid ( 17-05-2021 20:00 and 2 ), because row_number is ordered by timestamp.我在下面写了查询,它给出了当前和以前的修改值,但它给出了latest date和用户 ID( 17-05-2021 20:002 ),因为 row_number 是按时间戳排序的。

with v_rank as (    
    select * from (
        select
            id,
            a.rank as current_rank,
            b.rank as previous_rank,
            a.log_timestamp,
            a.log_username,
            row_number() over(partition by a.id order by a.log_timestamp) as rnum
        from
            user a
            inner join user b on a.id = b.id and a.log_timestamp > b.timestamp
            where
                a.rank != b.rank
            order by a.log_timestamp, b.timestamp
    ) where rnum = 1
)
select * from v_rank

Any suggestion on how can i get the correct timestamp(13-05-2021 14:10) and userid(2) .关于如何获得正确timestamp(13-05-2021 14:10)userid(2)的任何建议。 Edit: Rank can also be null, in that case i need to get the blank in query result.编辑:排名也可以是 null,在这种情况下我需要在查询结果中得到空白。

Expected output:预期 output:

在此处输入图像描述

You seem to want lag() with filtering:你似乎想要lag()过滤:

select u.*
from (select u.*,
             lag(rank) over (partition by id order by log_timestamp) as prev_rank
      from user u
     ) u
where rank <> prev_rank;

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