使用 python 将字典中的键和值写入 csv

Question

I have a dictionary with 2 keys are "text1" and "text2", the characteristic is key "text1" has a repeated character "A" but the number of element between 2 occurrence of "A" can be changed when I update dictionary "data" sometimes. I want to writer a header row in csv with all values from "A" to value before next "A", and the value from "text2" will be matched with column from header as below expected result in csv:

import csv
data={
    "text1":("A","mouse","cat","A","mouse","cat","A","mouse","cat"),
    "text2":(1,2,3,4,5,6,7,8,9)
}


with open("result.csv","w") as f:
    writer=csv.writer(f,delimiter=',',lineterminator='\n')
    writer_inline=csv.writer(f,delimiter=',',lineterminator=',')
    for i in range(0,len(data["text1"])):
        writer_inline.writerow([data["text1"][i]])
        if data["text1"][i]=="A" and i>1:
            continue

with open("result.csv","r") as f:
    print(f.read())

Answer 1

To write to csv file from your data dictionary, you can use this example:

import csv

data = {
    "text1": ("A", "mouse", "cat", "A", "mouse", "cat", "A", "mouse", "cat"),
    "text2": (1, 2, 3, 4, 5, 6, 7, 8, 9),
}

tmp = {}
for k, v in zip(data["text1"], data["text2"]):
    tmp.setdefault(k, []).append(v)

with open("result.csv", "w") as f_out:
    writer = csv.writer(f_out)
    writer.writerow(tmp.keys())
    writer.writerows(zip(*tmp.values()))

Creates result.csv :

A,mouse,cat
1,2,3
4,5,6
7,8,9

Screenshot: