考虑到 r 中的 dataframe 中的其他列条件，如何提取列的日期？

Question

I have a big dataset with 1200 rows, which looks like this:

Date	CAL_CALFIXO	FIXOCAL
2015-07-20	Yes	No
2015-07-21	Yes	No
2015-07-22	No	No
2015-07-23	No	Yes
2015-07-24	No	No
2015-07-25	Yes	Yes
2015-07-26	No	No
..........	...........	.......

The Date is in Date format.

My question is the following: how to extract the dates where CAL_CALFIXO and FIXOCAL are "Yes"? The code can have both columns CAL_CALFIXO and FIXOCAL together or separate.

My desired output would look like this (where at least one variable is "Yes"):

Date	CAL_CALFIXO	FIXOCAL
2015-07-20	Yes	No
2015-07-21	Yes	No
2015-07-23	No	Yes
2015-07-24	No	Yes
2015-07-25	Yes	Yes
..........	...........	.......

Any help will be much appreciated.

Answer 1

When you post an image with your data is a little difficult understand the structure of your data. You can review this link https://stackoverflow.com/help/how-to-ask .

Using your data and the library tidyverse I believe that I have your answer.

library(tidyverse)

df<-data.frame(Date=seq(as.Date("2015-07-20"), as.Date("2015-07-26"), by="day"),
           CAL_CALFIXO=c("yes","yes","no", "no", "no","yes", "no" ),
           FIXOCAL=c("no","no","no","yes","no","yes","no")) # The DF with your data

Date<-df%>%filter(.,  CAL_CALFIXO=="yes"&FIXOCAL=="yes")%>% #Filter extract the columns with the desired characteristics
  select(., Date)# with Select I am choosing to save only the Column Date in a new Dataframe.

My output is:

>Date
        Date
1 2015-07-25