使用 jq 拆分嵌套 JSON 对象的数组

Question

I'm trying to split an array of nested json objects using jq .我正在尝试使用jq拆分一组嵌套的 json 对象。 Could someone please help to resolve this issue and provide a better solution?有人可以帮助解决这个问题并提供更好的解决方案吗？

Sample input is:样本输入为：

{
  "storeId": "1412",
  "templateCheck": [
    {
      "rom": 37,
      "updateDate": "2021-05-09 07:53:17",
      "lhb": "2021-05-09 06:32:41",
      "templateCode": "REGULAR",
      "lId": "50-19-78-5C",
      "sk": "830066",
      "skUpdateDate": "2020-07-21 05:37:07",
      "battery": 30,
      "status": 1
    },
    {
      "rom": 37,
      "updateDate": "2021-05-09 07:54:02",
      "lhb": "2021-05-09 06:32:41",
      "templateCode": "REGULAR",
      "lId": "50-1B-FE-6E",
      "sk": "740541",
      "skUpdateDate": "2021-03-22 05:59:00",
      "battery": 30,
      "status": 1
    },
    {
      "rom": 37,
      "updateDate": "2021-05-09 07:52:05",
      "lhb": "2021-05-09 06:32:41",
      "templateCode": "REGULAR",
      "lId": "50-1C-22-6E",
      "sk": "846760",
      "skUpdateDate": "2021-05-08 03:34:22",
      "battery": 29,
      "status": 1
    }
  ]
}

Expecting output as:期望 output 为：

{
    "storeId": "1412",
    "templateCheck": [
      "rom": 37,
      "updateDate": "2021-05-09 07:53:17",
      "lhb": "2021-05-09 06:32:41",
      "templateCode": "REGULAR",
      "lId": "50-19-78-5C",
      "sk": "830066",
      "skUpdateDate": "2020-07-21 05:37:07",
      "battery": 30,
      "status": 1
    ]
}
{
    "storeId": "1412",
    "templateCheck": [
      "rom": 37,
      "updateDate": "2021-05-09 07:54:02",
      "lhb": "2021-05-09 06:32:41",
      "templateCode": "REGULAR",
      "lId": "50-1B-FE-6E",
      "sku": "740541",
      "skUpdateDate": "2021-03-22 05:59:00",
      "battery": 30,
      "status": 1
    ]
}
{
    "storeId": "1412",
    "templateCheck": [
      "rom": 37,
      "updateDate": "2021-05-09 07:52:05",
      "lhb": "2021-05-09 06:32:41",
      "templateCode": "REGULAR",
      "lId": "50-1C-22-6E",
      "sk": "846760",
      "skUpdateDate": "2021-05-08 03:34:22",
      "battery": 29,
      "status": 1
    ]
}

Answer 1

Sure it's possible.当然有可能。 Assuming there are no other top-level keys that you care about,假设没有您关心的其他顶级键，

jq '.storeId as $storeId | .templateCheck[] | { $storeId, templateCheck: [ . ] }'

does just fine to reproduce your example output, or maybe a little more generically (but more confusingly):可以很好地重现您的示例 output，或者更通用一点（但更令人困惑）：

jq '(. | del(.templateCheck)) as $o | .templateCheck[] | $o + { templateCheck: [.] }'

使用 jq 拆分嵌套 JSON 对象的数组

问题描述

1 个解决方案

解决方案1
1 已采纳 2021-05-19 18:50:23

使用 jq 拆分嵌套 JSON 对象的数组

问题描述

1 个解决方案

解决方案1 1 已采纳 2021-05-19 18:50:23

解决方案1
1 已采纳 2021-05-19 18:50:23