无法通过 xpath 或链接文本使用 selenium python 访问链接

Question

The Webpage

<div class="span3"> <div class="stat-panel"> <div class="stat-cell1 bg-stats1 valign-middle" style="text-align: center;"> <a href="co-op/coopjobs.htm"><strong>View and Apply for<br> Co-op Jobs</strong></a> </div> </div> </div>

This is a broader view of the code of that box, The clickable part seems to be the a tag and the strong tag. I'm not sure why xpath doesn't work but do you know how to implement find by text for the strong?

I'm not sure how to access the link above. I want to click on a link that is written using the code above with selenium webdriver python.

Does anyone know how to find the strong element using find by link text, im not sure how to implement that

Answer 1

XPATH:

//a[contains(@href, "co-op/coopjobs.htm")]

and click on it like this:

driver.find_element_by_xpath("//a[contains(@href, "co-op/coopjobs.htm")]").click()

for clicking on anchor tag, remember always linkText or partialLinkText is preferred.

Answer 2

This should work:

driver.find_element_by_xpath("//a[contains(@href,'co-op/coopjobs.htm')]").click()

If this doesn't work for you we need more information.
So, the above locator is not a unique.
You need to use the following:

driver.find_element_by_xpath("//a[contains(@href,'co-op/coopjobs.htm') and(contains(text(),'View and Apply for'))]").click()

Try this:

from selenium.webdriver.common.action_chains import ActionChains

element = driver.find_element_by_xpath("//a[contains(@href,'co-op/coopjobs.htm') and(contains(text(),'View and Apply for'))]")

actions = ActionChains(driver)
actions.move_to_element(element).perform()
element.click()