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在二叉树中查找最大高度/深度

[英]Finding max height/depth in Binary Tree

After going through the basics of Binary Tree, I define it in C++ as below:在了解了二叉树的基础知识后,我在 C++ 中定义如下:

struct Node
{
    int key;
    Node *left;
    Node *right;
}*left=NULL,*right=NULL;

int getDepth(Node* t)
{
  if (t == NULL)
    return 0;
  else
    {
      int lDepth = getDepth(t->left);
      int rDepth = getDepth(t->right);

      if (lDepth > rDepth)
        return(lDepth + 1);
      else 
        return(rDepth + 1);
    }
}
int main()
{
    // root
    Node* root = new Node();
    root->key = 1;
    
    // left subtree
    root->left = new Node();
    root->left->key = 2;
    root->left->left = new Node();
    root->left->left->key = 4;
    root->left->right = new Node();
    root->left->right->key = 5;
    
    // right subtree
    root->right = new Node();
    root->right->key = 3;
}

Now If I try to find maximum height/depth using this code, it returns 3 instead of 2. What may be the reason?现在,如果我尝试使用此代码找到最大高度/深度,它会返回 3 而不是 2。可能是什么原因? Also, Why I didn't find this way of assigning value to nodes anywhere?另外,为什么我没有找到这种为任何地方的节点分配价值的方式?

Edit: Adding requested code编辑:添加请求的代码

Two issues:两个问题:

1. You're incorrectly setting up the struct Node . 1.您错误地设置了 struct Node

To define a type Node where the members have initial values, your syntax is slightly wrong.要定义成员具有初始值的类型Node ,您的语法略有错误。 Instead, do:相反,请执行以下操作:

struct Node {
    int key = 0;
    Node *left = nullptr;
    Node *right = nullptr;
};

2. The height of the tree is 3. 2. 树的高度是 3。

Here's a visual representation of the tree you've created.这是您创建的树的可视化表示。 It has 3 levels.它有3个级别。

         1
        / \
       2   3
      / \
     4   5

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