如何遍历列表中的每两个元素，python3？

Question

for element1 in list_of_elements:
    for element2 in list_of_elements:
        if not element1 == element2:
             #do

I need a better solution, this cycle goes twice over the list.

Answer 1

for element1, element2 in permutations(list_of_elements, r=2):
    #do

It is a solution.