如何从具有大量属性的对象数组中获取“极简”对象数组

Question

I have an array, like this:

let x = [
    {id: 1, name: 'A', age: 34.. lots of other properties}, 
    {id: 2, name: 'B', age: 17.. }, 
    {id: 3, name: 'C', age: 54.. }
]

How can I get this output from it:

let output = [
    {id: 1, name: 'A'}, 
    {id: 2, name: 'B'}, 
    {id: 3, name: 'C'}
]

I mean, I can iterate throut it, and push new objects into a new array. But I was thinking if there's a better way to do it..

Answer 1

More generally, for any set of attributes, the idea is called “pick” and "pluck" in lodash and underscore...

 let x = [ {id: 1, name: 'A', age: 34 }, {id: 2, name: 'B', age: 17 }, {id: 3, name: 'C', age: 54 } ] function pick(object, ...attributes) { const filtered = Object.entries(object).filter(([k, v]) => attributes.includes(k)) return Object.fromEntries(filtered); } function pluck(array, ...attributes) { return array.map(el => pick(el, ...attributes)) } console.log(pluck(x, 'id', 'name'))

Answer 2

You can use .map

 let x = [ {id: 1, name: 'A', age: 34.,}, {id: 2, name: 'B', age: 17., }, {id: 3, name: 'C', age: 54., } ]; console.log(x.map(({id, name}) => ({id, name})));