如果 user_num2 大于 8，则为 user_num2 分配 5。打印“user_num2 小于或等于 8。”

Question

Task: Print "user_num1 is negative." if user_num1 is less than 0. End with newline. Assign user_num2 with 5 if user_num2 is greater than 8. Otherwise, print "user_num2 is less than or equal to 8.". End with newline.

Problem: I've attached my code and for some reason when user_num2 = 8 it does not output the print statement as depicted in the output image. What am I doing wrong?

Attempted code:

user_num1 = int(input())
user_num2 = int(input())

if user_num1 < 0:    
    print('user_num1 is negative.')
elif user_num2 <= 8:
      print('user_num2 is less than or equal to 8.')
else:
     user_num2 = 5

print('user_num2 is', user_num2)

Answer 1

Each user gets its own "if" statements. Try this out:

user_num1 = int(input())
user_num2 = int(input())

if user_num1 < 0:
    print('user_num1 is negative.')

if user_num2 > 8:
    user_num2 = 5
else:
    print('user_num2 is less than or equal to 8.')

print('user_num2 is', user_num2)

Answer 2

This is what I understand from the text: user_num1 and user_num2 tests are independant, so each has its own "if" statement. Otherwise the user_num2 test is not executed when user_num1 < 0.

user_num1 = int(input())
user_num2 = int(input())

if user_num1 < 0:    
    print('user_num1 is negative.')

if user_num2 <= 8:
    print('user_num2 is less than or equal to 8.')
else:
    user_num2 = 5

print('user_num2 is', user_num2)