[英]segmentation fault python main.py
I wrote a c++ module witch should be imported into Python.我写了一个 c++ 模块,应该将其导入 Python。 Below are both Codes, the C++ part and the Python part.
下面是两个代码,C++ 部分和 Python 部分。 The C++ function
method_sum
should return the double of a value to python. C++ function
method_sum
应该将值的双精度值返回给 python。
module.cpp:模块.cpp:
#define PY_SSIZE_T_CLEAN
#include <Python.h>
static PyObject *method_sum(PyObject *self, PyObject *args) {
const int *prop;
if (!PyArg_ParseTuple(args, "i", &prop)) return NULL;
int result = *prop + *prop;
return Py_BuildValue("i", result);
}
static PyMethodDef ModuleMethods[] = {
{"sum", method_sum, METH_VARARGS, "description of the function"},
{NULL, NULL, 0, NULL}
};
static struct PyModuleDef module = {
PyModuleDef_HEAD_INIT,
"module",
"description of the module",
-1,
ModuleMethods
};
PyMODINIT_FUNC PyInit_module(void) {
return PyModule_Create(&module);
}
main.py:主要.py:
import module
print(module.sum(18))
setup.py:设置.py:
from distutils.core import setup, Extension
setup(name='module', version='1.0', ext_modules=[Extension('module', ['module.cpp'])])
I changed method_sum
to the following and main.py
prints 36 instead of segfaulting.我将
method_sum
更改为以下内容,并且main.py
打印 36 而不是 segfaulting。
static PyObject *method_sum(PyObject *self, PyObject *args) {
int prop;
if (!PyArg_ParseTuple(args, "i", &prop)) return NULL;
int result = prop + prop;
return Py_BuildValue("i", result);
}
The following also works and prop
is still a pointer like in the code in the question.以下也适用,并且
prop
仍然是问题中代码中的指针。
static PyObject *method_sum(PyObject *self, PyObject *args) {
const int *prop = new int;
if (!PyArg_ParseTuple(args, "i", prop)) {
delete prop;
return NULL;
}
int result = *prop + *prop;
delete prop;
return Py_BuildValue("i", result);
}
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