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然后在 promise 解决/拒绝之前执行块(Promise.allSettled)

[英]then block executed before promise resolves/reject (Promise.allSettled)

note: The issue was in not putting return on map so not related with Promise注意:问题在于没有在map上返回,因此与Promise

I'm trying to to make multiple, independent api calls in parallel.我正在尝试并行进行多个独立的 api 调用。 Promise.allSettled(<promise array>) looked right for this scenario. Promise.allSettled(<promise array>)看起来适合这种情况。 This is my first try to ever use promise, so I might have made some obvious mistakes.这是我第一次尝试使用 promise,所以我可能犯了一些明显的错误。

The issue: then was executed before promise resolve/reject.问题:然后在 promise 解决/拒绝之前执行。 Things were printed in order indicated with circled numbers.事情是按照带圆圈的数字表示的顺序打印的。

// typescript version: 3.9.9
async function startTest(testInfo: someObjectType[]): Promise<string> {
  const arrPromise = testInfo.map((info) => { startRun(info) });
  console.log(arrPromise); // ① prints [undefined, ..., undefined]

  (Promise as any)
    .allSettled(arrPromise)
    .then(async (results: any) => { // it was omitted but await was used in then block
      console.log('[resolved all]'); // ②
      for (const result of results) {
        if (result.status == 'fulfilled') {
          console.log(`resolve ${result.value}`); // ③ undefined
        }
      }
  });
  return 'some string data';
}

async function startRun(info: someObjectType): Promise<testResult|string> {
  try {
    const resp = await httpRequestHandler.post(`<request url>`, {request header});
    if (resp.statusCode == 200) return 'some test result object'; 
  } catch (ex) {
    console.log(`[failed]=${info.testName}`); // ④
    return Promise.reject(`${info.testName}: ${ex}`);
  }
}

It's not related to Promise.allSettled :它与Promise.allSettled

 const arrPromise = testInfo.map((info) => { startRun(info) }); console.log(arrPromise); // ① prints [undefined, ..., undefined]

arrPromise should be an array of promises, but isn't: you're not returning them from the map callback. arrPromise应该是一组承诺,但不是:您不会从map回调中返回它们。 Use利用

const arrPromise = testInfo.map((info) => { return startRun(info) });
//                                          ^^^^^^

or或者

const arrPromise = testInfo.map(info => startRun(info));

or just要不就

const arrPromise = testInfo.map(startRun);

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