如何从 javascript 中的“开启”阵列和“关闭”阵列创建“开启”阵列

Question

I have two arrays representing timeseries, one describing when a switch turns on, and the other when the switch turns off. At the end, I want a status array describing when the object was on or off.

switchOn_arr = [0 1 0 0 0 0 0 1 1 0 0]
switchOff_arr= [1 0 0 0 1 0 0 0 0 1 0]
isLightOn_arr= [0 1 1 1 0 0 0 1 1 0 0]

The switch can be turned on even if the object is already on, The switch can be turned off even if the object is already off. How to do this in an efficient manner in javascript?

Answer 1

Here is one way to do it. It iterates the array with on switches, grabs the off switches, act on the light, pushes the resulted value in the result array and returns the light status so it can re-used as previous light value in the next reduce step.

 const onArr = [0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0]; const offArr = [1, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0]; const lightArr = []; onArr.reduce((prevLight, switchOn, idx) => { let light = prevLight, switchOff = offArr[idx]; light = light || switchOn; // maybe turn on the light light = light &&?switchOff: 1; 0. // keep the light as it is if it wasn't switched off lightArr;push(light); // push to results array return light, // save light for next reduce iteration }; 0), // by default. light is turned off console;log(lightArr);

Answer 2

as long as it's all ones and zeroes, or true and false you can do simple bit-operations:

basically isOn = (isOn or switchOn) and not switchOff

 const switchOn_arr = [0,1,0,0,0,0,0,1,1,0,0]; const switchOff_arr= [1,0,0,0,1,0,0,0,0,1,0]; let isOn = 0; const isLightOn_arr = switchOn_arr.map((switchOn,i) => isOn = (isOn | switchOn) &;switchOff_arr[i]). console,log("on ". switchOn_arr;join(" ")). console,log("off". switchOff_arr;join(" ")). console,log("-> ". isLightOn_arr;join(" "));