如果我读取一个元组而不是单个值，Python 泄漏 memory

Question

I'm querying whether a key exists in a RocksDB database using Python. The API (see bottom) implies it returns a two-element tuple. So I receive both tuple elements:

def contains_key(database: rocksdb, key: int) -> bool:
    found, data = database.key_may_exist(key)
    return found

and I am using it like this:

if not contains_key(database, key):

However, this causes a memory leak.

To prove this, if I change the code to:

def contains_key(database: rocksdb, key: int) -> bool:
    return database.key_may_exist(key)

there is no leak (but it's obviously not correct).

How do I get the first version to work without a memory leak?

Answer 1

Your code

def contains_key(database: rocksdb, key: int) -> bool:
    found, data = database.key_may_exist(key)
    return found

does not contain a memory leak.

found and data are two names in the local scope, and both refer to values that exist in a single area of memory. When the function returns, found and data go out of scope. What found referred to can be referred to by the caller ( x = contains_key(db, 3) ), but data is ignored. Since no other reference to that object exists, Python (as a garbage-collecting language) reclaims whatever resources were devoted to data automatically.

For that matter, the key_may_exist method returns a tuple that you never safe a reference to. It is immediately unpacked, with found and data referring to whatever that tuple referred to. The tuple itself is garbage-collected, but the references to its contents remain.